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If a man leans over a cliff and throws a rock upward at 4.9 m/s. Neglecting air resistance, what is the rock's speed one second later?

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    v1 = velocity one second later
    vi = initial velocity of rock = 4.9 m/s
    t = time in seconds
    g = acceleration due to gravity = -9.8 m/s^2
    v1 = vi + gt

    Plug the numbers in and solve for v1.

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