# CHEM 152

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Calculate the molar solubility of calcium carbonate in 0.10 M Ca(NO3)2. (Ksp= 2.8 x 10-8)

• CHEM 152 -

CaCO3 ==> Ca^+2 + CO3^-2

Ksp = (Ca^+2)(CO3^-2)
Let S = solubility CaCO3, then
Ca^+2 comes from two places. It is S from CaCO3 and it is 0.1 M from Ca(NO3)2 so total Ca^+2 concn is S+0.01. Finally, S = concn CO3^-2
Solve for S which is solubility CaCO3.

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