11.31) solve for the new pressure when each of the following temperature changes occurs, with n and V constant:
a. a gas sample has a pressure of 1200 torr at 155 celcius. what is the final pressure of the gas after the temperature has droped to 0 celcius?
1200 x12 celcius/0 celcius=
(P1/T1) = (P2/T2) for all of them.
Don't forget to use Kelvin for temperature. Note correct spelling of celsius.
To solve for the new pressure when the temperature changes, we can use the combined gas law equation, which states:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
Where:
P1 and P2 are the initial and final pressures.
V1 and V2 are the initial and final volumes.
T1 and T2 are the initial and final temperatures.
In this case, we have:
P1 = 1200 torr (the initial pressure at 155 Celsius)
T1 = 155 Celsius (the initial temperature)
T2 = 0 Celsius (the final temperature)
Since the value of V is constant, we don't need to consider it in this case.
Now, let's plug in the values into the equation and solve for P2:
(1200 torr * V) / (155 Celsius) = (P2 * V) / (0 Celsius)
To eliminate the V term from both sides, we can multiply both sides of the equation by V:
1200 torr / 155 Celsius = P2 / 0 Celsius
Now, to solve for P2, we can multiply both sides of the equation by 0 Celsius to get rid of the denominator:
1200 torr / 155 Celsius * 0 Celsius = P2
Since anything multiplied by 0 is always 0, the final pressure (P2) will be 0 torr after the temperature drops to 0 Celsius.
Therefore, the final pressure of the gas after the temperature drops to 0 Celsius is 0 torr.