what volume (in L) of 0.150 M KCl solution is required to completely react with 0.150 L of a 0.175 M Pb(NO3)2 solution according to the following balanced chemical equation?
2KCl (aq) + Pb(NO3)2 (aq) --> PbCl2 (s) + 2 KNO3 (aq)
1. Calculate moles Pb(NO3)2. mols = M x L.
2. Using the coefficients in the balanced equation, convert moles Pb(NO3)2 to moles KCl.
3. Convert mols KCl to L. M = mols/L.
you are right but when you divide 0.052 by 0.150 the answer will be 0.35 L.
okay so the solution would be.
0.150 M KCl x 0.175 M Pb(NO3)2/ 1 M KCL x 0.150 L/0.175 M Pb(NO3)2 = 0.023 L?
No. Don't try to do it all at once. Do it in steps as I've suggested.
0.15 x 0.175 will give you the correct mols Pb(NO3)2 but your conversion factor does not convert to moles KCl. There are 2 moles KCl/1 mole Pb(NO3)2 according to your balanced equation. I don't know what the last term means.
Well, let's break this down, shall we?
According to the balanced chemical equation given, we need 2 moles of KCl to react with 1 mole of Pb(NO3)2.
First, let's find the number of moles of Pb(NO3)2 in 0.150 L of a 0.175 M solution.
Number of moles = volume (L) × concentration (M)
Number of moles of Pb(NO3)2 = 0.150 L × 0.175 M = 0.02625 moles of Pb(NO3)2
Now, since the ratio is 2:1, we need twice the number of moles of KCl for the reaction.
Number of moles of KCl = 2 × 0.02625 moles of Pb(NO3)2 = 0.0525 moles of KCl
Now, let's find the volume of a 0.150 M KCl solution that contains 0.0525 moles of KCl.
Volume (L) = moles / concentration
Volume = 0.0525 moles / 0.150 M = 0.35 L
So, 0.35 liters of the 0.150 M KCl solution is required to completely react with 0.150 liters of the 0.175 M Pb(NO3)2 solution. That's the volume needed to whisk those chemicals away, like a magician! Ta-da!
To find the volume of the KCl solution required to react with the Pb(NO3)2 solution, we need to use the balanced chemical equation and the concept of stoichiometry.
In the balanced chemical equation, we can see that 2 moles of KCl react with 1 mole of Pb(NO3)2 to form 1 mole of PbCl2. This means that the stoichiometric ratio between KCl and Pb(NO3)2 is 2:1.
First, let's calculate the number of moles of Pb(NO3)2 in the given volume of the solution:
moles of Pb(NO3)2 = concentration of Pb(NO3)2 × volume of Pb(NO3)2 solution
moles of Pb(NO3)2 = 0.175 M × 0.150 L = 0.02625 moles
Since the stoichiometric ratio between KCl and Pb(NO3)2 is 2:1, we need twice the number of moles of KCl than Pb(NO3)2 to completely react.
moles of KCl required = 2 × moles of Pb(NO3)2
moles of KCl required = 2 × 0.02625 = 0.0525 moles
Now, we can calculate the volume of 0.150 M KCl solution needed using its concentration:
volume of KCl solution = moles of KCl required / concentration of KCl solution
volume of KCl solution = 0.0525 moles / 0.150 M = 0.35 L
Therefore, a volume of 0.35 liters of the 0.150 M KCl solution is required to completely react with 0.150 L of the 0.175 M Pb(NO3)2 solution.
my teacher insists that we do it that way, i don't really understand it but i try!
so it would come out to be 0.026 moles Pb(NO3)2. Then, converting Pb(NO3)2 into KCl it would come out to be 0.052 Moles KCl. Then divide 0.052 by 0.150 which would equal 0.15 L?