Post a New Question

geometry

posted by .

In the diagram below, the length of the legs AC and BC of right triangle ABC are 6cm and 8cm, respectively.Altitude CD is drawm to the hypotenuse of triangle ABC.
what is the lenght of AD to the nearest tenth of a centimeter?

  • geometry -

    3,4,5 right trisangle so
    hypotenuse = 10
    Draw it and note similar triangles ABC, CBD, ACD
    call AD = x
    then BD = 10-x
    the altitude CD = sqrt (36-x^2)
    the altitude CD = sqrt (64 -(10-x)^2)
    so
    36-x^2 = 64 - (10-x)^2
    36 - x^2 = 64 - ( 100 -20 x + x^2)
    36 - x^2 = -36 + 20 x - x^2
    72 = 20 x
    x = 72/20 = 3.6

  • geometry -

    ur mom

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question