You draw two cards from a standard deck of 52 cards and replace the first one before drawing the second. Find the probability of drawing a 4 for the first card and a 9 for the second card. Round your answer to the nearest thousandth.
0.006
0.039
0.019
0.155
0.026
which wwould it be
1/169 = .005917
which according to the nearest thousandth is
006
since you are replacing the card, the second prob is the same as the first
prob(4, then 9 ) = (4/52)(4/52) = (1/13)^2 = 1/169
You do the button-pushing.
still questionable not understanding how to get the problem with the correct answer
To find the probability of drawing a 4 for the first card and a 9 for the second card, we need to determine the probability of each individual event and then multiply them together.
There are 52 cards in a standard deck, and each card has an equal probability of being drawn. Therefore, the probability of drawing a 4 for the first card is 1/52.
Since we replace the first card before drawing the second, each event is independent. This means that the probability of drawing a 9 for the second card is also 1/52.
To find the probability of both events occurring, we need to multiply the probabilities together:
P(4 and 9) = P(4) * P(9) = (1/52) * (1/52) = 1/2704 ≈ 0.00037.
Rounded to the nearest thousandth, the probability of drawing a 4 for the first card and a 9 for the second card is approximately 0.000. Therefore, the closest option from the given choices is "0.000".