trig
posted by James .
Write the following equation in standard form and identify the type of conic:
9y^2  4x^2 + 8x + 18y + 41 = 0

9y^2  4x^2 + 8x + 18y + 41 = 0
4x^2  8x  9y^2  18y  41 = 0
4(x^2  2x + ......)  9(y^2 + 2y + .... ) = 41
let's "complete these squares"
4(x^2  2x + 1)  9(y^2 + 2y + 1 ) = 41 + 4  9
4(x1)^2  9(y+1)^2 = 36
divide by 36
(x1)^2/9  (y+1)^2/4 = 1
If you are studying conics you should now be able to identify the conic and state its properties.
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