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A 5 m long see saw has a child whose mass is 25 kg sitting on one end. How far in meters from the center should a 70 kg adult sit on the opposite side for the see saw to balance?

  • physics -

    Let A = the child and B = adult person.
    To balance this beam, the moment of the right hand side (B) must equal the moment of the left hand side (A).

    M(A) = M(B)
    m(A)*g*2.5 = m(B)*g*d(B)
    62.5 = 70*d(B)

    => d(B) = 70/62.5 = 1.12m

    I hope this will help

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