algebra
posted by Sheila .
The length of a rectangular field is 7 meters more than twice its width. If the perimeter is 140 meters, find the dimensions of the field.

31.5 and 38.5

Oh wait, I read it wrong, sorry.

width  x
length  x+7
2(x + x+7) = 140
easy to solve... 
and I read it wrong as well, lol
width  x
length  2x+7
2(x + 2x+7) = 140
easy to solve... 
P=2(l+w)
width=w
length=2w+7
(w)+(w)+(2w+7)+(2w+7)=140
6w+14=140
6w=14014
6w=126
w=126/6
w=21(width)
l=2w+7
2*21=42+7=49 (length) 
I am 100% sure that my answer is right!!
By the way,in what grade is the person who asked this question (just wondering...) 
width= x
lengtth=x+2
so
x(x+2)=170
easy to solve....................
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