what is the theoretical value for the M of acetic acid in vinegar if the vinegar is 5% acetic acid by a % mass value.

Additional info: the experimental M of the acetic acid in vinegar is 0.80M
Thank you!!

see above

Under Stacey

To calculate the theoretical value for the molarity (M) of acetic acid in vinegar, we need to use the percent mass of acetic acid and the molar mass of acetic acid.

Since vinegar is 5% acetic acid by mass, it means that 5g of acetic acid is present in 100g of vinegar.

Next, we need to calculate the moles of acetic acid present in 5g. To do this, we divide the mass of acetic acid by its molar mass.

The molar mass of acetic acid (CH3COOH) is approximately 60.05 g/mol.

So, the moles of acetic acid can be calculated as follows:
moles = mass / molar mass
moles = 5g / 60.05 g/mol

Now, we have the number of moles of acetic acid.

The next step is to calculate the volume of vinegar required to prepare 1 liter (1000 mL) of the 0.80 M acetic acid solution.

Molarity (M) is defined as moles of solute (acetic acid) per liter of solution.

So, the moles of acetic acid required for 1 liter of 0.80 M solution can be calculated as follows:
moles = Molarity * volume (in liters)
moles = 0.80 mol/L * 1 L

Now, we set up an equation to find the moles of acetic acid in the given 5g of vinegar and the volume of vinegar (in liters) required to prepare 1 liter of the 0.80 M solution.

5g / 60.05 g/mol = 0.80 mol/L * volume

Rearranging the equation and solving for the volume, we get:

volume = (5g / 60.05 g/mol) / 0.80 mol/L

Now, we can calculate the volume of vinegar needed.

Finally, the calculated volume of vinegar can be converted to a mass percentage by dividing the mass of acetic acid by the total mass of vinegar and multiplying by 100%.

So, the theoretical value for the molarity of acetic acid in vinegar can be calculated by dividing the moles of acetic acid by the calculated volume of vinegar.

Hope this explanation helps!