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algebra

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during the first part of a trip a canoeist travels 64 miles at a certain speed. the canoeist travels 11 miles on the second part of the trip at a 5 mph slower. the total time for the trip is 2 hrs. what speed on each part of the trip

  • algebra -

    Given:

    d1 = 64
    d2 = 11
    t(total) = 2
    s1 = ?
    s1 = s2 + 5

    Ask yourself, what t really is?
    t(total) = d1/s1 + d2/s2

    substituting s1 as s2 + 5:
    2 = 64/(s2+5) + 11/(s2)

    Common denominator: multiply s(s+5)/s(s+5)and you eventually get:
    2s^2 - 65s - 55 = 0

    Same old quadratic formula:
    s2 = 33.325 mph
    s1 = s2 + 5 = 38.325 mph

    Plug the # back in the original equation... 2 = 2, checked!

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