a gaseous sample occupies 32.4 mL at -23 degrees C and 0.75 atm. What volume will it occupy at STP?
(P1V1)/T1 = (P2V2)/T2
Don't forget to use T1 and T2 in Kelvin.
76
To determine the volume of a gaseous sample at STP (Standard Temperature and Pressure), we need to use the Ideal Gas Law equation, which is as follows:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
In this case, we are given the initial volume (V1 = 32.4 mL) and temperature (T1 = -23 degrees C), as well as the pressure (P1 = 0.75 atm). We want to find the volume at STP, which means the pressure (P2) will be 1 atm and the temperature (T2) will be 273 K.
Now, let's set up the equation and plug in the values:
P1V1/T1 = P2V2/T2
0.75 atm * 32.4 mL / (-23 + 273) K = 1 atm * V2 / 273 K
Simplifying, we get:
(0.75 * 32.4) / 250 = V2 / 273
24.3 / 250 = V2 / 273
V2 = (24.3 / 250) * 273
V2 ≈ 26.5304 mL
Therefore, the volume of the gaseous sample at STP will be approximately 26.5304 mL.