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If 950 mL of 0.800 M aqueous Na2CO3 and 920 mL of 0.565 M aqueous HCl are reacted stoichiometrically according to the balanced equation, how many milliliters of 0.800 M aqueous Na2CO3 remain? Round your answer to 3 significant figures.

Na2CO3(aq) + 2HCl(aq) ¡æ CO2(g) + 2NaCl(aq) + H2O(l)


Molar Mass (g/mol)
Na2CO3 105.99
HCl 36.461

Molar Volume (L)
22.4 at STP

Gas Constant
(L.atm.mol-1.K-1)
0.0821

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