Math
posted by DezQ .
Assuming that a typical popular music CD comprises 12 songs each of 8500 KB, what would the effective transmission speed need to be capped at in order to extend the download time to 2 hours? Express your final answer in bits per second, using scientific notation correct to two decimal places

12 songs * 8500 *10^3 Bytes/song = 1.02*10^8 Bytes = 8.16*10^8 bits
Transmission speed
= 8.16*10^8 bits/7200 s
= 1.13*10^5 bits/s