chemistry

posted by .

if you have 720 g of the compound CaBr2 how many moles of it do you have

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chemistry

    When 1.24g of an organic compound with the formula CxHyOz is burned in excess oxygen, 1.76g of carbon dioxide and 1.08g of water vapor are obtained. What is the empirical formula of the compound?
  2. bobpursly, check please,math

    do you mean like this: 720/(V-30) + 720/(V+30) = 10 Get a common denominator of (v-30)(v+30) then multiplying both sides by that, then (v-30)(v+30)X 720(V+30) + (v-30)(v+30) X 720(V-30)=(v-30)(v+30)X 10(v-30)(v+30) then multily out, …
  3. Chemistry

    How many moles of each of the following are needed to provide 1.0 osmol?
  4. Chemistry UGH

    Help please! I can't solve any of these, would someone be as kind as to show me the answers?
  5. chemistry

    Give the name of each of the following binary ionic compound: a. KCI b. CaBr2 c. Li2 O d. MgCl2
  6. chemistry

    How would you find the empirical formula for this... a substance was found by analysis to contain 20% by mass calcium and 80% by mass bromine. Would it be CaBr2?
  7. chemistry

    A solution was made by dissolving 62.07 grams of a compound in 500.0 g of water. The compound was not ionic. The freezing point of the solution was measured and found to be – 1.86oC. Using the Kf value in your textbook , the molar …
  8. chemistry final step

    If you have 24.98 grams of P and 74.99 grams of O2, how many moles of each compound do you have present?
  9. Chemistry

    112.00g of nitrogen gas is reacted with an excess or abundant amount of oxygen gas. The single product, a gas, is determined to have a mass of 431.92 g. Additional experiments showed that the product consisted of 2.0 moles. a) how …
  10. Chem 3

    Prepared by disolving 60g CaBr2 280g H2O the final volume of tje solution is 300ml. Calculate the mole of the solution, normality ,weight % of CaBr2,molality ,moles of fraction of CaBr2 ,moles fraction of H2O

More Similar Questions