posted by Anonymous .
A 65-kg boy is sitting on a seesaw 0.6 m from the balance point. How far from the balance point should a 40-kg girl sit so that the seesaw remains balance?
The magnitude multiplied by the direction should be the same on both sides. So for the boy, it would be (65 kg x 0.6)= 39. Therefore the mass of the girl multiplied by the distance should equal 39 as well. So (39=X x 40). x = 0.975