calculus
posted by Justin .
Write the complex number 4 x 3^1/3  4i in exponential form.
I'm not sure how I use euler's formula to solve for this. A brief explanation would be greatly appreciated.

Does the "x" indicate multiplication, or is it an unknown? Does the 4 multiply (3^1/3)  4i or just 3^(1/3) ?
Find the magnitude of the complex number first. Call it C. Then write your number as
C*e^(i*z)
using Euler's formula.
e^iz = cos z + i sin z
The magnitude of
4 *(3^1/3  4i)
is
4*sqrt[3^(2/3) + 16] = 17.01
so you can write
4 *(3^1/3  4i)
= 17.01*(0.3392 +0.9406 i)
Now find the number z (in radians) for which
cos z = 0.3392 and sinz = 0.9406
It will be in the second quadrant
z = 1.9169
The answer would be 17.01 exp(1.9169i),
but it depends upon whether I interpreted what you wrote correctly. You need to use parenthese and explain the "x" 
Sorry for the misunderstanding. The X is a multiplication sign and the 4 is multiplied to the cubed root of 3.
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