Math.
posted by Annonom .
Use the distributive property of multiplication over addition to rewrite the sum as a product of two factors, where one of the factors is a sum.
20a2  16a  8
A) a(20a2  16a  8)
B) 4(5a2  4a  2)
C) 4(5a2  4  2a)
D) 4a(5a  16  8a)

When you have parenthesis and you "distribute", you are multiplying each part. Example: for A, you multiply a with 20a2 and get 20a3, then you multiply a with the 16a and get 16a2 and multiply the a with 8 and get 8a, so your answer is 20a316a28a for A, so the answer is not A. Do the same for B,C,D and I can check your answer if you want.

Awesome I got it so it is B because it will all equal up to the 20a2  16a  8

Yes, good job!!
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