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how to solve y= 3cos2x + 5
pls help me

  • math -

    Is that really cos(2x) or do you mean cos^2 x?

    I will assume that you really do mean cos(2x). In that case

    cos(2x) = cos^2 x - sin^2 x
    = 2 cos^2 x -1

    y = 6 cos^2x -3 + 5 = 6 cos^2 x - 2
    cos^2 x = (y+2)/6
    cos x = sqrt[(y+2)/6)]

    You can use that to solve for x, if that is what the question is all about.

    You cannot solve a single equation for both x and y.

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