Am using the inventory method at moment but am stuck on how fill i the inventory for
__Agl+__Fe2(CO3)3--> __Fel3+__Ag2CO3
I think the brackets are throwing me
Hows this
element b4 after
------------------------------------
Ag 1 2
l 1 3
Fe 6 1
CO 3 3
I don't know if this is right???
Can you fill in the missing pieces of the puzzle Thanks Andy
__Agl+__Fe2(CO3)3--> __Fel3+__Ag2CO3
You're just making these things hard on yourself..
1.Look at CO3 on the left. There are 3 so add a 3 on the right for Ag2CO3.
2. That means 6 Ag so place a 6 for AgI on the left.
3. That means 6I so 2 FeI3 on the right.
4. I didn't check and I ALWAYS do but I'll leave it for you to check.
thanks dr bob
Andy
To balance the chemical equation:
__Agl + __Fe2(CO3)3 → __Fel3 + __Ag2CO3.
Let's go step by step:
1. Start with the individual elements and count how many you have on each side of the equation: Ag, l, Fe, C, O.
2. Begin by balancing the element that appears only once on each side of the equation. In this case, it is the Ag (silver).
From your table, it seems that you have correctly determined that you need 2 Ag on the right side. Thus, fill in the blanks on the left side with a coefficient of 2 for Ag:
2Agl + __Fe2(CO3)3 → __Fel3 + __Ag2CO3.
3. Next, move on to the element that appears in multiple compounds on only one side of the equation. In this case, it is the l (iodine) that appears in the compound Agl.
Since you need 2 Ag atoms, you also need 2 l atoms. So fill in the blanks on both sides with a coefficient of 2 for l:
2Agl + __Fe2(CO3)3 → __Fel3 + __Ag2CO3.
4. Now, focus on Fe (iron). According to your table, there are 6 Fe atoms on the left side and only 1 Fe on the right side.
To balance the Fe atoms, fill in the blanks with a coefficient of 6 for Fe on the right side:
2Agl + 6Fe2(CO3)3 → __Fel3 + __Ag2CO3.
5. Finally, address the remaining elements, C (carbon) and O (oxygen), which are present in the CO3 group.
From your table, you have correctly determined that CO3 needs a coefficient of 3 on both sides. So, fill in the blanks with a coefficient of 3 for CO3:
2Agl + 6Fe2(CO3)3 → __Fel3 + __Ag2CO3.
Now you can see that you have balanced the equation for Ag, l, Fe, and CO3. However, the equation is still not fully balanced because there are coefficients missing for Fel and Ag2CO3.
To balance the equation completely, you need to calculate the coefficients for Fel and Ag2CO3 by applying the same balancing principles. Once you have done that, you will have a fully balanced equation.