A 5.1 kg bowling ball and a 7.1 kg bowling ball rest on a rack 1.07 m apart.

(a) What is the force of gravity exerted on each of the balls by the other ball?

(b) At what separation is the force of gravity between the balls equal to 2.0 10-9 N?

part b says 2.0 E-9

F = G M1 M2 / d^2

= 6.67 * 10^-11 * 5.1 * 7.1 / 1.07^2

part b

2*10^-9 = 6.67*10^-11*5.1*7.1/d^2
solve for d

find the force of gravity between two 7.26kg bowling balls separated by 3m

To calculate the force of gravity exerted by one object on another, we can use Newton's law of universal gravitation:

F = G * (m1 * m2) / r^2

Where:
F is the force of gravity
G is the gravitational constant (6.67430 × 10^-11 N m^2/kg^2)
m1 and m2 are the masses of the objects
r is the separation distance between the objects

(a) Let's calculate the force of gravity exerted on each of the balls by the other ball:

For the first ball (5.1 kg) exerting force on the second ball (7.1 kg):
F1 = G * (m1 * m2) / r^2 = (6.67430 × 10^-11 N m^2/kg^2) * (5.1 kg * 7.1 kg) / (1.07 m)^2

For the second ball (7.1 kg) exerting force on the first ball (5.1 kg):
F2 = G * (m1 * m2) / r^2 = (6.67430 × 10^-11 N m^2/kg^2) * (5.1 kg * 7.1 kg) / (1.07 m)^2

(b) To find the separation distance at which the force of gravity between the balls is equal to 2.0 * 10^-9 N, we can rearrange the formula:

r = √(G * (m1 * m2) / F)

Substituting the values into the formula:
r = √((6.67430 × 10^-11 N m^2/kg^2) * (5.1 kg * 7.1 kg) / (2.0 * 10^-9 N))

Now, you can plug in the numbers and solve the equation with a calculator to find the separation distance.