Post a New Question

Physics

posted by .

A 5.1 kg bowling ball and a 7.1 kg bowling ball rest on a rack 1.07 m apart.

(a) What is the force of gravity exerted on each of the balls by the other ball?

(b) At what separation is the force of gravity between the balls equal to 2.0 10-9 N?

  • Physics -

    part b says 2.0 E-9

  • Physics -

    F = G M1 M2 / d^2
    = 6.67 * 10^-11 * 5.1 * 7.1 / 1.07^2

  • Physics -

    part b
    2*10^-9 = 6.67*10^-11*5.1*7.1/d^2
    solve for d

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question