how many moles of acetic acid are in 15.05mL, 45.13mL, and 75.22mL of titrated vinegar?
I wonder if the moles are there whether the vinegar is titrated or not?
M x L = moles.
To determine the number of moles of acetic acid in each volume of titrated vinegar, we need to know the concentration of the acetic acid solution.
Here's how you can calculate the number of moles step by step:
1. Obtain the molarity (concentration) of the acetic acid solution used for titration. This information should be provided in the question or in the experimental setup. Let's assume the molarity is given as "C" in molarity (mol/L) units.
2. Convert the given volumes of titrated vinegar from milliliters (mL) to liters (L) since molarity is given in terms of liters. Divide each volume by 1000 to convert them.
For example:
- 15.05 mL = 15.05 mL / 1000 = 0.01505 L
- 45.13 mL = 45.13 mL / 1000 = 0.04513 L
- 75.22 mL = 75.22 mL / 1000 = 0.07522 L
3. Calculate the number of moles (n) using the formula:
n = C * V
where C is the concentration in molarity, and V is the volume in liters.
For each volume provided, multiply the molarity (C) with the volume in liters (V) to obtain the number of moles:
- Moles of acetic acid in 15.05 mL = C * 0.01505 L
- Moles of acetic acid in 45.13 mL = C * 0.04513 L
- Moles of acetic acid in 75.22 mL = C * 0.07522 L
Remember, you need to know the molarity (C) to calculate the number of moles accurately.