trig

posted by .

find, to the nearest degree, the solution set of 4 cos^2x-1=0 in the intervak between )degrees and 360degrees.

  • trig -

    4 cos^2x-1=0
    cos^2 x = 1/4
    cosx = ± 1/2
    In I x = 60
    in II , x = 180-60 = 120
    in III, x = 180+60 = 240
    in IV , x = 360-60 = 300

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. trig

    Give the measure of the acute angle with each given value to the nearest tenth of a degree. cos A = 0.1 (84.3 degrees) sec D = 1.8 (65.3 degrees) That is all it gives :( How would I go about solving this?
  2. advanced functions(trig)

    solve for x, to the nearest degree, in the interval 0degres less than andequal to x greater than and equal to 360degrees. cos^2x=1 4cos^2x=1
  3. trig

    Find, to the nearest degree, the solution set of 3sin^2x = 5 cosx+1 over the demain {x|0 degrees < or = to x which is < 360 degrees}
  4. trig

    find to the nearesr degree, all values of x between 0 degrees and 360 degrees that satisfy the equation 2sinx + 4 cos 2x =3
  5. trig

    find, to the nearest minute, the solution set of 4 cos x + 5 = 6 sec x over the domain 0 degrees which is less than or eaual to x which is less than 360 degrees
  6. trig

    find, to the nearest minute, the solution set of 1- sin x = 3 cos^2 x over the domain 0 degrees to 360 degres
  7. trig

    ind, to the nearest minute, the solution set of 4 cos x + 5 = 6 sec x over the domain 0 degrees
  8. HELPPPPPPP (TRIG)

    find, to the nearest minute, the solution set of 1- sin x = 3 cos^2 x over the domain 0 degrees to 360 degrees
  9. trig/math

    If A is between 270degrees and 360degrees, and cos A=12/13, find the exact value of: sin2a, cos2a, sin1/2a, cos1/2a
  10. trig

    To the nearest degree, all of the following angles are solutions of the equation 2sin x + 4 cos 2x =3 except: (1) 40 degrees (2) 150 degrees (3) 166 degrees (4) 194 degrees

More Similar Questions