Electronic Instrumentation

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Calculate the force in Newtons that exists between a positive charge of 2C and a negative charge of 5.2 X 10^19 electrons separated by a distance of 25 cm.

  • Electronic Instrumentation -

    f=kqq/r^2

    I will be happy to critique your work.

  • Electronic Instrumentation -

    I'm having trouble finding Q2.
    -5.2 x 10^19 x 6.2 x 10 ^18?

  • Electronic Instrumentation -

    The "Q2" charge, of the 5.2*10^19 electrons, is
    -5.2*10^19*1.6*10^-19 C/electron
    = -8.32 Coulombs

    Your number of 6.2*10^18 is the number of electrons per Coulomb. If you had divided by that number instead of multiplying, you would have gotten the right answer.

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