Unit Cells

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Copper has a unit cell volume of (47.453 A^3) and a face centered unit cell. How would I go about finding the volume of atoms within the unit cell? Would you use Avogadro's # somehow?

  • Unit Cells -

    I don't get the 47.453 A^3 for volume. That seems far too large (of course that depends upon what A stands for).
    Whatever the volume, then
    V1/3 = length of an edge of the unit cell = a. Then 4r = a(21/2).
    When you have found r (radius of the atom), then volume of the atom = (4/3)*pi*r3.

  • Unit Cells -

    4r = a(21/2) and
    volume of the atom = (4/3)*pi*r3

  • Unit Cells -

    I got it thank you!
    The A^3 was suppose to stand for ångström
    cubed...

  • Unit Cells -

    what does the pi stand for?

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