Unit Cells
posted by CHeM .
Copper has a unit cell volume of (47.453 A^3) and a face centered unit cell. How would I go about finding the volume of atoms within the unit cell? Would you use Avogadro's # somehow?

I don't get the 47.453 A^3 for volume. That seems far too large (of course that depends upon what A stands for).
Whatever the volume, then
V^{1/3} = length of an edge of the unit cell = a. Then 4r = a(2^{1/2). When you have found r (radius of the atom), then volume of the atom = (4/3)*pi*r3.} 
4r = a(2^{1/2}) and
volume of the atom = (4/3)*pi*r^{3} 
I got it thank you!
The A^3 was suppose to stand for ångström
cubed... 
what does the pi stand for?
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