posted by Chem .
what must be the current in amperes to plate out 7.437g of Al from am aqueous solution of Al3+ in 5.4x10^2 minutes?
A x seconds = coulombs.
It will take 96,485 coulombs to plate (26.98/3) g Al.
Coulombs = 96,485 x (7.437 x 3/26.98) = ??
Substitute into the first equation and solve for A. Time is 540 min x 60 s/min.