A thimb is 23.0 cm from a concave mirror. The focal point is 9.0 cm. Where is the image located?
Please subject, not grade level.
Use the formula 1/Do + 1/Di = 1/f
and solve for the image distance Di.
Do = 23 cm
f = 9.0 cm
To determine the location of the image formed by a concave mirror, we can use the mirror equation, which is:
1/f = 1/do + 1/di
Where:
- f is the focal length of the mirror
- do is the object distance (the distance between the object and the mirror)
- di is the image distance (the distance between the image and the mirror)
In this case, the focal length (f) is given as 9.0 cm, and the object distance (do) is given as 23.0 cm.
Substituting the known values into the mirror equation, we can solve for the image distance (di):
1/9.0 = 1/23.0 + 1/di
To get the image distance (di), we need to rearrange the equation and solve for di:
1/di = 1/9.0 - 1/23.0
Calculating this expression, we get:
1/di = (23 - 9)/(9 * 23)
1/di = 14/207
Taking the reciprocal of both sides, we find:
di = 207/14
Therefore, the image is located at a distance of 207/14 cm from the concave mirror.