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the statue of liberty is 150 feet tall, and stands on a 150 foot pedestal. How far from the base should you stand to have the statue subtend the largest possible angle at your camera lens, assuming the camera is held 5 feet off the ground and the ground is flat?

  • math -

    Before I type out a rather lengthy solution, does your book have an answer of x = 206.8 feet ?

  • math -

    Hi, this is a worksheet problem so i do not have the answer to it. It came with a pic though. Here is the link. Thanks.
    img121.imageshack.us/i/dsc01000vu.jpg/

  • math -

    nice, I had appr. the same figure,
    let's call the other angle b

    then tanb = 145/x
    tan(Ø+b) = 295/x

    we know tan(Ø+b - b) = (tan(Ø+b) - tanb)/(1 + tan(Ø+b)tanb)
    tanØ = (295/x - 145/x) / ( 1 + (295/x)(145/x))
    = (150/x) / (x^2 + 42775)/x2)
    = 150x/(x^2 + 42775)

    sec^2Ø dØ/dx = [ (x^2+42775)(150 - 2x(150x) ]/(x^2 + 42775)^2
    = 0 for a max/min of Ø

    [ (x^2+42775)(150 - 2x(150x) ]/(x^2 + 42775)^2 = 0
    (x^2+42775)(150 - 2x(150x) = 0
    150x^2 + 6416250 - 300x^2 = 0
    x^2 = 42775
    x = 206.8

    then tanØ = (150(206.8)) / (206.3^2 + 42775)
    tan Ø = .362632
    Ø = 19.9° or 3479 radians

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