posted by Megan .
NH3(g) + O2(g) NO2(g) + H2O(g)
Consider the above unbalanced equation. What volume of NH3 at 950. mm Hg and 33.5°C is needed to react with 190. mL of O2 at 485 mm Hg and 143°C?
1. Balance the equation.
2. Convert 190 mL of O2 at the conditions listed to moles. Use PV = nRT
3. Using the coefficients in the balanced equation, convert moles O2 to moles NH3.
4. Now convert moles NH3 to liters at the conditions listed using PV = nRT, then change to mL.