posted by .

2y^2*3xy^3 divided by 3x^2y^4

## Similar Questions

1. ### Math

I have no clue how to do this as no values were given and im confused. can someone explain plz?

I struggle in the sciences and was wondering what I could do over the summer self studying wise to prepare for 10th grade chem?
3. ### Derive

Find the derivative of sin(2x + 3y)= 3xy + 5y-2. I have this so far 1) cos(2x+3y) * d/dx (2x+3y)= 3xy' + 3y + 5y' 2) cos (2x+3y) * [2 + 3y']= 3xy' + 3y + 5y' 3) 3y' cos (2x+3y) + 2cos(2x+3y)= 3xy' + 3y + 5y' 4) 3xy' + 5y' - (3y(cos(3x+3y)= …
4. ### Simultaneous equation

X+y+z=1......(1) x^2+y^2+z^2=35........(2) x^3+y^3+z^3=97.........(3) solution but from 3 (x^3+y^3)=(x+y)^3-3xy(x+y)......(4) puting 4 into 3 bck (x+y)^3-3xy(x+y)+z^3=97.......(5) now from 1 x+y=1-z......(6) putin 6 into 7 we have …

6. ### Mathematics

Simplify: 1: (-12xy2z)(3xy) 2: -12xy2z divided by 3xy 3: 2x(2x - 5) 4: -2x(2x-5)
7. ### Mathematics

I'm struggling with these! Please help! :) Simplify: 1: (-12xy2z)(3xy) 2: -12xy2z divided by 3xy 3: 2x(2x - 5) 4: -2x(2x-5)
8. ### Mathematics

I'm struggling with these! Please help! :) Simplify: 1: (-12xy2z)(3xy) 2: -12xy2z divided by 3xy 3: 2x(2x - 5) 4: -2x(2x-5)
9. ### math

Simplify Please: 1: (-12xy2z)(3xy) 2: -12xy2z divided by 3xy 3: 2x(2x - 5) 4: -2x(2x-5)