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AALGEBRA

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NEED HELP SOLVING 3h/2 = 30 and
3(3+r)= 2r+4

so 3x3=9,3xr=3r = 2r+4
9+3r=2r+4
9-9+4=3r+2r ?????

  • AALGEBRA -

    first one:
    3h/2 = 30
    multiply both sides by 2
    3h = 60
    divide both sides by 3
    h = 20

    second one:
    3(3+r)= 2r+4
    expand
    9 + 3r = 2r + 4
    3r - 2r = 4 - 9
    r = -5

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