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At a party, there were 105 handshakes. If each person shook hands exactly once with every other person, how many people were at the party?

  • math -

    for n people there will be C(n,2) handshakes

    C(n,2) = 105
    n!/(2!(n-2)!) = 105
    n(n-1)/2 = 105
    n^2 - n - 210 = 0
    (n-15(n+14) = 0
    n = 15 or n=-14, but n > 0

    so there were 15 people

  • math -

    Good

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