Pre Calculus

posted by .

Prove that 2/square root 3cosx-sinx=sec(pi/6-x)

  • Pre Calculus -

    work on the right side

    RS = 1/cos(π/6 - x)
    = 1/)cosπ/6cosx + sinπ/6sinx)
    = 1/(√3/2cosx + 1/2sinx)
    = 2/(√3cosx + sinx)

    did you make a typing error?
    I tested your equation for some value of x, it did not work out, mine did.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Trig........

    I need to prove that the following is true. Thanks (cosx / 1-sinx ) = ( 1+sinx / cosx ) I recall this question causing all kinds of problems when I was still teaching. it requires a little "trick" L.S. =cosx/(1-sinx) multiply top and …
  2. Pre-Calculus

    (not sure how to type square root of) square root of 3x - 4 = (x-4)^2-3 Normally, I either take the square root of both sides or I square both sides. Since one side of the equation is square root of 3x-4 and the other side is (x-4) …
  3. pre-calculus

    What is the polar form of the equation 3x - 4y = 12?
  4. Trig Help

    Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)] =[sinx+sin^2x]/[sinx+1] =[sinx+(1-cos^2x)]/[sinx+1] =?
  5. Pre-Calculus

    How would you prove/Verify this Identity. x=theta (cosx+sinx-sin^3x)/(sinx)=cotx+cos^2x
  6. Pre Calculus

    Solve the inequality sinx>square root x.
  7. college pre-calculus

    simplify: square root (4/3)-square root (3/4) A. 2-sqaure root(3)/2 square root (3) B. square root (7/12) C. square root (3)/6 D. 2/square root (3) which answer?
  8. Calculus

    If y=3/(sinx+cosx) , find dy/dx A. 3sinx-3cosx B. 3/(sinx+cosx)^2 C. -3/(sinx+cosx)^2 D. 3(cosx-sinx)/(sinx+cosx)^2 E. 3(sinx-cosx)/(1+2sinxcosx)
  9. Pre-Calculus

    Solve 0 = 3x^2 + 5x -1 by completing the square. Express your answer as exact roots. 3(x^2 + 5/3 + 25/36) = -1 (x+ 5/6)^2 = 37/36 sq root( x + 5/6)^2 = sq root (37/36) x + 5/6 = +- sq root 37/6 x = -5/6 +- square root 37 /6 <--- …
  10. Calculus

    A rectangle is bounded by the x axis and the semicircle = square root 25-x^2. What length and width should the rectangle have so that its area is a maximum?

More Similar Questions