College Chemistry

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Calculate the electrode potential of a copper half-call containing 0.05M Cu(NO3).

E^0 Cu2+/Cu = 0.337 V

  • College Chemistry -

    E = Eo - (0.0592/n)log[(Cu)/(Cu^+2)]
    Substitute 2 for n and 0.05 M for Cu^+2 and 0.337 for Eo. Solve.

  • College Chemistry -

    Am I solving for Cu or do I plug a value in for that also?

  • College Chemistry -

    Answered above.

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