posted by helpanderson .
Calculate the heat released when 10.0 g of water at 25.0°C cools to ice at 0.0°C. The specific heat of water is 1.00 cal/(g × °C); the heat of fusion is 80.0 cal/g; and the heat of vaporization is 540.0 cal/g.
You don't need the heat of vaporization to do that calculation.
It takes 10g*1Cal/C g*10C = 100 Cal heat release to reduce the temperature ot 0C, and another 80 Cal/g*10 g = 800 Cal to freeze it. The sum is 900 Cal
how many calories are released when 25.0 g of water at 100 celcius cools to 30 celcius.