How many grams of sodium nitrate, NaNO3 are needed to make 250 ml of .500 M solution? MM of NaNO3 is 85 g/mol?? I'm not sure which equation to use, help please?
M= moles/L
0.500 = moles/0.250 L
Solve for moles.
Then moles = grams/molar mass. Solve for grams.
To calculate the amount of sodium nitrate needed to make a certain concentration, you can use the formula:
Molarity (M) = moles/volume (L)
First, convert the volume from milliliters (ml) to liters (L):
250 ml = 250/1000 = 0.25 L
Next, rearrange the formula to solve for moles:
moles = Molarity (M) x volume (L)
Given:
Molarity (M) = 0.500 M
Volume (L) = 0.25 L
Substitute the values into the equation:
moles = 0.500 M x 0.25 L
moles = 0.125 mol
Finally, use the molar mass of sodium nitrate to convert moles to grams:
Molar mass (NaNO3) = 85 g/mol
grams = moles x molar mass
grams = 0.125 mol x 85 g/mol
grams = 10.625 g
Therefore, you would need 10.625 grams of sodium nitrate to make a 250 ml solution with a concentration of 0.500 M.
To determine the number of grams of sodium nitrate (NaNO3) needed to make a 250 mL solution with a concentration of 0.500 M, we can use the equation:
C = (m/V)
where:
C is the concentration in moles per liter (M)
m is the mass in grams
V is the volume in liters
First, convert the given volume from milliliters to liters by dividing by 1000:
250 mL ÷ 1000 = 0.250 L
Then, rearrange the equation to solve for the mass:
m = C * V
Substitute the values into the equation:
m = 0.500 M * 0.250 L
Now, we need to convert moles to grams using the molar mass of sodium nitrate (NaNO3), which is given as 85 g/mol:
m = 0.500 mol/L * 0.250 L * 85 g/mol
Simplify the equation:
m = 10.625 g
Therefore, you would need approximately 10.625 grams of sodium nitrate (NaNO3) to make a 250 mL solution with a concentration of 0.500 M.