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A certain radioactive material decays exponetially. The percent, P, of the material left after t years is given by P(t)= 100(1.2)^-t
a)Determine the half life of the substance

  • Calculus -

    From the equation we can see that the original amount was 100 units
    So we want to know when that amount becomes 50
    50 = 100(1.2)^-t
    .5 = 1.2^-t
    log(.5)= log(1.2^-t)
    log(.5)= -tlog(1.2)
    -t = log(.5)/log(1.2)
    = -3.8

    so t = 3.8 years is the half-life time

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