urgent calculus
posted by Anonymous .
The position of a particle moving in a straight line is given by s(t) = 2sint  cost , from 0 to 2 pi
where s is the displacement in metres and t is the time in seconds. Find the absolute max and absolute min displacements.

s'(t) = 2cost + sint
= 0 for a max/min
sint = 2cost
sint/cost = 2
tant = 2
t = π  1.107 = 2.0344 or
t = 2π  1.107 = 5.176
s(2.0344) = 2.236
s(5.176) = 2.236
so the max is ...
and the min is ....
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