# Trig

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Solve for x in the interval [0,2pi) sin^2x+2cosx=2

• Trig -

sin^2x+2cosx=2
1 - cos^2x + 2cosx - 2 = 0
cos^2x - 2cosx + 1 = 0
(cosx - 1)^2 = 0
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.
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cosx = 1

Can you take it from there?

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