Trig
posted by Tina .
Solve for x in the interval [0,2pi) sin^2x+2cosx=2

sin^2x+2cosx=2
1  cos^2x + 2cosx  2 = 0
cos^2x  2cosx + 1 = 0
(cosx  1)^2 = 0
.
.
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cosx = 1
Can you take it from there?
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