if 3/5 of a number exceeds its 2/7 by 44 ,find the number
Lex x be the unknown nummber. Solve the equation
(3/5)x = (2/7)x + 44
Create a common denominator for the two fractions, and move both to the left side.
(21 - 10)x/35 = 44
11x/35 = 44
Divide both sides by 11.
x/35 = 4
Now multiply both sides by 35 for the answer.
If 3/5 of a number exceeds 2/7 by 44, find the number
At a cricket test match 2/7 of the spectators were in a covered place while 15000 were in open.Find the total number of spectators
Find the amount and the compound interest on rs 8000 for 1 year at 10% per annum,compounded half-yearly
(3/5)x=(2/7)x+44
(3/7)x-(2/7)x=44
(21-10)x/35=44
(11/35)x=44
x=44*35/11
x=140
Potty
To solve this problem, we need to set up an equation. Let's assume the number we are looking for is represented by 'x'.
According to the problem, 3/5 of this number exceeds its 2/7 by 44. Mathematically, we can represent this as:
(3/5) * x = (2/7) * x + 44
Now, let's solve this equation step by step to find the value of 'x'.
Multiply through by the least common multiple (LCM) of the denominators of 5 and 7, which is 35, to eliminate fractions:
35 * (3/5) * x = 35 * (2/7) * x + 35 * 44
Cancel out the denominators:
21x = 10x + 1540
Next, move all the terms containing x to one side of the equation:
21x - 10x = 1540
Combine like terms:
11x = 1540
Finally, isolate x by dividing both sides of the equation by 11:
x = 1540 / 11
Calculating this, we find:
x = 140
Therefore, the number we were looking for is 140.