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What is the pH of a solution in which 25 mL of .10 M NaOH is added to 15 mL of .10 M HCl?

I have calculated the amount of moles of each, but I'm not really sure where to go from there. Thanks!

  • Chemistry -

    moles NaOH = M x L = 0.1 x 0.025 = 0.0025
    moles HCl = 0.015 L x 0.1 M = 0.0015
    So if they react 1:1 (from the equation), which one will be used up? And which is the one in excess? The excess will determine the OH if it is NaOH or it will determine H if it is HCl. Then moles remaining of that reagent/L solution is M and go to pH or pOH from there.

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