Chemistry II

posted by .

The equlibrium constant Kc for the reaction: has the value of 4.00 at 500K. If a mixture of 1.00 mol CO and 1.00 mol H2O is allowed to reach equilibrium at this temperature in a 1.00L flask, calculate the equilibrium concentrations of each species in the flask.

  • Chemistry II -

    You should have shown the reaction. I assume it is
    CO(g) + H2O(g) ==>H2(g) + CO2(g)
    If not, just ignore what follows.

    Set up an ICE chart and solve.
    initial:
    CO = 1.00 mol/L
    H2O = 1.00 mol/L
    CO2 = 0
    H2 = 0

    change:
    CO = -x
    H2O = -x
    H2 = x
    CO2 = x

    equilibrium:
    CO = 1-x
    H2O = 1-x
    CO2 = x
    H2 = x

    Post your work if you get stuck.

  • Chemistry II -

    Kc=(x)(x)/(1-x)(1-x)

    What is x in this equation and is is 4.0 Kc?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physical Science

    In a certain reaction 1.5 mol of CO and 1.5 mol of H2O are placed in a 2,0 dm3 sealed vessel. Equilibrium is established at a temperature of 1 000 C. The equilibrium reaction equation is CO(g) + H2O(g) = CO2(g) + H2(g) The value of …
  2. chem

    For the equilibrium reaction: CO(g)+H2O(g)<=>CO2(g)+H2(g) the Keq value at 690°C is 10.0. A mixture of 0.300 mol of CO, 0.300 mol of H2O, 0.500 mol of CO2 and 0.500 mol of H2 is placed in a 1.0 L flask. a)Write the Keq expression …
  3. CHEM

    For the equilibrium reaction Co(g)+H2O(g)<=>CO2(g)+H2(g) the Keq value at 690°C is 10.0. A mixture of 0.300 mol of CO, 0.300 mol of H2O, 0.500 mol of CO2 and 0.500 mol of H2 is placed in a 1.0 L flask. a) Write the Keq expression …
  4. Chemistry

    The equlibrium constant K, for the reaction, H2 + CO2 <-> H20 + CO, is 4.2 at 1650 degrees C. Initially, 0.80 mol H2 and 0.80 mol CO2 are injected into a 5.0L flask. Calculate the concentration of each species at equilibrium.
  5. chemistry

    A mixture of 0.100 mol NO, 0.200 mol H2 and 0.0800 mol N2 were placed in a 2.00L reaction vessel, heated, and allowed to come to equilibrium conditions. At equilibrium, the molar concentration of N2 was 0.0500 mol/L. Calculate Kc for …
  6. Chem 12

    0.300 mol of S2 and 0.310 mol of C are placed in a 1.00 L flask and allowed to reach equilibrium according to this reaction: S2(g) + C(s) ⇔ CS2(g) At equilibrium, 0.271 mol of CS2 is present. The value of Keq for the reaction …
  7. Chemistry

    Carbon monoxide and hydrogen react according to the equation: CO(g) + 3H2(g) CH4(g) + H2O When 1.00 mol CO and 3.00 mol H2 are placed in a 1L flask at 1200K and allowed to come to equilibrium, the reaction mixture is found to contain …
  8. chem12

    1.0 mol of each of the gases, CO, H20, CO2 and H2 are placed in a 2.00L container and allowed to reach equilibrium. It is found at equilibrium 0.40 mol of CO is present. Calculate the value of K eq for the system. C0(g) + H20(g)--- …
  9. chem 12

    1.0 mol of each of the gases, CO, H20, CO2 and H2 are placed in a 2.00L container and allowed to reach equilibrium. It is found at equilibrium 0.40 mol of CO is present. Calculate the value of K eq for the system. C0(g) + H20(g)--- …
  10. Chemistry

    For the reaction: 2NO(g) + H2(g) <=> N2O(g) + H2O(g) + energy Write the equilibrium constant expression for the reaction. I wrote: [N2O][H2O] / [NO]2 [H2] This reaction takes place at 25°C. At this temperature the concentration …

More Similar Questions