algebra
posted by vera .
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?

algebra 
Damon
they both go distance d
first one travels time = t+3
second one travels time = (t)
d = 6 (t+3) = 10(t)
6 t + 18 = 10 t
4 t = 18
t = 9/2 = 4.5 hr
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