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Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?

  • algebra -

    they both go distance d
    first one travels time = t+3
    second one travels time = (t)
    d = 6 (t+3) = 10(t)
    6 t + 18 = 10 t
    4 t = 18
    t = 9/2 = 4.5 hr

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