# physical chemisry

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Estimate the freezing point of 150 cm3 of water sweetened with 7.5g of sucrose
(C12H11O22). (Kf for water is 1.86 K kg mol-1; density of water is 1gcm-3)

• physical chemisry -

moles sucrose = grams/molar mass. Solve for moles.
molality = moles sucrose/kg solvent. Solve for molality.

delta T = Kf*molality.
solve for delta T and from there the freezing point.

• physical chemisry -

6.11*10^-5 K

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