Math

posted by .

A satellite is launched into orbit 200 kilometers above the Earth.The orbital velocity of a satellite is given by the formula v=√GmE/r, where v is the velocity in meters per second, G is a given constant, mE is the mass of Earth, and r is the radius of the satellite"s orbit. The radius of Earth is 6,380,000 meters. What is the radius of the satellite's orbit in meters?

  • Math -

    From your given information,
    r = 6,380,000 + 200,000 = 6,580,000 m or
    ....6,380 + 200 = 6,580 km.

    The velocity required to maintain a circular orbit around the Earth may be computed from the following:

    Vc = sqrt(µ/r)

    where Vc is the circular orbital velocity in feet per second, µ (pronounced meuw as opposed to meow) is the gravitational constant of the earth, ~1.40766x10^16 ft.^3/sec.^2, and r is the distance from the center of the earth to the altitude in question in feet. Using 3963 miles for the radius of the earth, the orbital velocity required for a 250 miles high circular orbit would be Vc = 1.40766x10^16/[(3963+250)x5280] = 1.40766x10^16/22,244,640 = 25,155 fps. (17,147 mph.) Since velocity is inversely proportional to r, the higher you go, the smaller the required orbital velocity.

    Insert your data to derive your orbital velocity.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physics

    A satellite of mass 220 kg is launched from a site on Earth's equator into an orbit at 200 km above the surface of Earth. (a) Assuming a circular orbit, what is the orbital period of this satellite?
  2. Physics

    A satellite of mass 210 kg is launched from a site on Earth's equator into an orbit at 210 km above the surface of Earth. (a) Assuming a circular orbit, what is the orbital period of this satellite?
  3. Geometry

    A satellite has-recently been placed in a nearly circular orbit 2000 kilometers above the earth’s surface. Given that the radius of the earth is approximately 6400 kilometers and that the satellite completes its orbit in 12 hours, …
  4. Math WORD PROBLEM

    The time in hours it takes a satellite to complete an orbit around the earth varies directly as the radius of the orbit (from the center of the earth) and inversely as the orbital velocity. If a satellite completes an orbit 860 miles …
  5. physics

    A satellite of mass 225 kg is launched from a site on Earth's equator into an orbit at 200 km above the surface of Earth. (The mass of the Earth is 5.98 1024 kg, and the radius of the Earth is 6.38 103 km.) (a) Assuming a circular …
  6. physics

    A satellite of mass 205 kg is launched from a site on Earth's equator into an orbit at 200 km above the surface of Earth. (a) Assuming a circular orbit, what is the orbital period of this satellite?
  7. Math

    When a satellite is h kilometres above Earth,the time,t,in minutes,to complete one orbit is given by the formula t=Root of (6370+h)^3/6024 a) A telecommunications satellite is placed 30 km above Earth. How long does it take the satellite …
  8. Math

    a satellite traveling in a circular orbit 2000 kilometers above the earth completes one orbit every 3 hours. assume the earth is a sphere and its radius is 6400 kilometers. find the angular velocity of the satellite
  9. math

    The orbital velocity of a satellite is given by v=√GM/R+h, where G= 6.67*10^-11 Nm^2kg^2, is the Universal Gravitational Constant, M=6*10^24 kg, is the mass of Earth, R=6.38*10^3 km, the orbit of the satellite, and h is artificial …
  10. math

    The orbital velocity of a satellite is given by v=√GM/R+h, where G= 6.67*10^-11 Nm^2kg^2, is the Universal Gravitational Constant, M=6*10^24 kg, is the mass of Earth, R=6.38*10^3 km, the orbit of the satellite, and h is artificial …

More Similar Questions