math
posted by johnica martin .
still having a hard time understand these? please help?
Logx10 + logx8logx5=4
Log3256log327=x
Log 2+ 3log 5log 25=x

math 
Damon
add logs to multiply, subtract to divide
logx (10*8/5) =4
logx (16) = 4
in general base^ logx = x
so
16 = x^4
x = 16^(1/4) = (2*2*2*2)^1/4 = 2 
math 
Damon
Log3 256log3 27=x
same as last question, subtract is divide
log3 (256/27) = x
256/27 = 3^x
I bet you have a typo because 27 is 3^3 but 256 is nothing to the 3 so have to use calculator
anyway
9.48 = 3^x
log10 (9.48) = x log10 (3)
.9768 = x * .4771
x = .9768/.4771 
math 
Damon
base 10 I assume
Log 2+ 3log 5log 25=x
log 2 + log 125  log 25 = x
log (250/25) = x
log 10 = 1 = x 
math 
johnica martin
ok so by your previous help i tried to solve this problem
Log32 56log32 7=x (log base 32)
what i did was 57/7=8
so in log form i got log 32 8=x ( log base 32)
then changed it to exponential form to 32^x=8
x= 0.6
correct? 
math 
johnica martin
yes i do have a typo
Log32 56log32 7=x
and my work is above 
math 
Damon
log 32 (8) = x
8 = 32^x
2^3 = 2^5x
x = 3/5 = 6/10 = 0.6 yes
I suspected you did not need a calculator :) 
math 
Damon
It helps if things like 2^3 = 8 and 2^5 = 32 are part of your tool box.

math 
Damon
also very common
3^3 = 27
5^3 = 125 
math 
johnica martin
sorry to bug you but i think this may be the last problem
2log4 x=3 (log base 4)
i got log16^x=3
16^3=x
x=4096
right? 
math 
Damon
log4 (x^2) = 3
x^2 = 4^3 = 64
x = 8 
math 
Blake
log 32 x = 6/10

math 
Blake
log 625 3/4 = x
Respond to this Question
Similar Questions

math
write as a single logarithm: 2logbase3(1/x)+(1/3)logbase3(square root of x) please show the steps to solving this. thanx. remember that 1 log (AxB) = log A + Log B (same base) 2 log (A/B) = log A  log B 3 log A^n = n log A use these … 
Calculus
Find the inverse of each relation: y = (0.5)^(x+2) and y = 3log base 2 (x3) + 2 For the first one I got y=log base 0.5 (x+2)...but the answer in the back of the textbook says that it is not x+2, but x2. Can someone tell me why it … 
Algebra 2
how do not understand how to do this Log X + Lob (X3) = 1 I know I do this Log X(X3)=1 then I do this Log X^(2)  3X = 1 then I do this 2 Log (X3X) = 1 then 2 Log (2X) = 1 then (2 Log (2X) = 1)(1/2) Log (2X) = 1/2 then (Log (2X) … 
Mathematics
Prove that log a, log ar, log ar^2 is an a.p. Is the following below correct? 
Math Help Please
Which of the following expressions is equal to log (x sqrty)/z^5 A. log x + log (1/2) + log y– log 5 – log z B. log [x + (1/2)y – 5z] C. log x + (1/2)log y – 5 log z d. [(1/2) log x log y]/(5 log z) 
math(Please help)
1) use the properties of logarithms to simplify the logarithmic expression. log base 10 (9/300) log  log 300 log 9 = 2 log 3 log 300 = log 3 + log 100 = log 3+2 I just do not know how to put these together now! 
math
Logarithm!!! Select all of the following that are true statements: (a) log(2x) = log(2) + log(x) (b) log(3x) = 3 log(x) (c) log(12y) = 2 log(2) + log(3y) (d) log(5y) = log(20y) – log(4) (e) log(x) = log(5x) – log(5) (f) ln(25) … 
Precalc
how to write each expression into a single logarithm. 3log[4]x^(2) + (1/2)log[4]ã(x) the answer is: (25/4)log[4]x steps please 
Math
I'm having a hard time with this problem. The book tells you the answer is 5, but I don't know how they got there. log(x+25)= 1+ log(2x7) 
Math (precelc 12)
Write the expression as a single logarithm: 3log(a)log(b)(1/2)log(c) I want to check my answer. I got log(a^3/bc^(1/2))