posted by Jen .
If 50.0mL of 1.60M HCl was added to 50.0mL of 1.80M NaOH, calculate the molarity of the resulting NaCl solution. (Hint: resulting solution has a volume of 100 mL)
moles HCl = M x L
moles NaOH = M x L
Determine moles NaCl formed, then
M NaCl = moles/L
How do you determine the moles of just NaCl? and is the moles of HCl and NaOH just the molar mass? Thanks
You aren't following instructions.
moles HCl = M x L. You have molarity given in the problem as well as liters (actually milliliters and you convert to liters).
moles NaOH = M x L.
HCl + NaOH ==> NaCl + H2O
The equation tells you that 1 mol HCl reacts with 1 mol NaOH to produce 1 mol NaCl. You look at moles HCl and moles NaOH you have and based on the above ratio you decide how many moles NaCl are formed. (One of the materials is a limiting reagent). Then from moles NaCl formed, divide by L of solution (50 mL + 50 mL = 100 mL = 0.100 L) to get M which is moles/L.
How do you know that the NaCl has 100 ml. How much volume does the water which is also a product have?
If you are struggling with these kinds of questions ,, that means you are not trying to understand chemistry!! Just try to understand like a maths!!
If you're struggling to spell Silentmist, that means you're retarded and should immediately kill yourself.