1/3(9 + g) = g+1
can you please show me the steps and answer for this question?
1/3(9 + g) = g+1
3 + 1/3g = g + 1
2 = g - 1/3g
2 = 2/3g
2 / (2/3) = g
2 * 3/2 = g
3 = g
thank you :)
You're welcome.
Sure! To solve the equation 1/3(9 + g) = g + 1, we can follow these steps:
Step 1: Distribute the 1/3 to both terms inside the parentheses.
(1/3) * 9 + (1/3) * g = g + 1
Simplifying, we get:
3 + (1/3)g = g + 1
Step 2: Move all the terms with g to one side of the equation and the constant terms to the other side.
(1/3)g - g = 1 - 3
Combining the terms on the left side, we have:
(1/3 - 1)g = -2
Step 3: Simplify the left side by finding a common denominator for (1/3 - 1).
(1/3 - 3/3)g = -2
(-2/3)g = -2
Step 4: Divide both sides by (-2/3) to solve for g.
g = (-2) / (-2/3)
To divide by a fraction, we invert the fraction and multiply:
g = (-2) * (3/-2)
Simplifying, we get:
g = -3
Therefore, the solution to the equation 1/3(9 + g) = g + 1 is g = -3.