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calc-kinematics

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if a particle moves along a line so that at time t where t [0,pi] its position is given by s(t)=-4cost-t^2/2+10 what is the velocity of the particle when its acceleration is zero?

so i found
v(t) = 4sint-t
a(t)=4cost-1 = 0 solved for t plugged it into v(t) and i got the wrong answer i got 3.2 something but the choices are


-5.19
.74
1.32
2.55
8.13

please help thank you

  • calc-kinematics -

    Did you have your calculator set to radians ?

    I get
    t = arcsin(1/4)
    = 1.318116

    then
    v(1.318116) = 4sin(1.318116) - 1.318116
    = 2.55486

    close to one of the choices,
    (they should have rounded to 2.56)

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