Trig.
posted by Shane .
Help with this problem please. I don't get it at all.
A ship is heading due north at 12 mph. The current is flowing southwest at 4mph. Find the actual bearing and speed of the ship.

Are you studying vectors?
I see a triangle with triangle ABC with AB vertical with length 12, angle B = 45 degrees, and BC = 4
by cosine law:
b^2 = 4^2 + 12^2  2(4)(12)cos45
= 92.1177
b = 9.598
Sos the actual speed of the ship is 9.6 mph
Use the Sine Law to find angle A for the bearing
(I had 17.14 degrees) 
The bearing would be 36017.14= 342.86 due to the fact that the bearing scale is different than the unit circle.